nyatakan dalam pangkat positif!
a.
[tex] \: ( - 4)^{ - 2} x^{3}y^{ - 2} [/tex]
b.
[tex] {2}^{5} a ^{ - 3} b^{5}c ^{ - 2} [/tex]
![]()
= (-4)^-2 x^3 y^-2
= 4^-2 x^3 y^-2
= 1/4^2 . x^3 . 1/y^2
= 1/16 . x^3 . 1/y^2
= 1/16x^3 . 1/y^2
= x^3 / 16y^2
kalau kurang jelas bilang ya [answer.2.content]
a.
[tex] \: ( - 4)^{ - 2} x^{3}y^{ - 2} [/tex]
b.
[tex] {2}^{5} a ^{ - 3} b^{5}c ^{ - 2} [/tex]
Penjelasan dengan langkah-langkah:
[tex]a.( - 4) { - }^{2} { \times }^{3} y { - }^{2} \\ = ( - 4) { - }^{2} { \times }^{3} y { - }^{2} \\ = 4 { - }^{2} { \times }^{3} y { - }^{2} \\ = \frac{1}{ {4}^{2} { }} . { \times }^{3} . \frac{1}{ {y}^{2} } \\ = \frac{1}{16} . { \times }^{3} . \frac{1}{ {y}^{2} } \\ = \frac{1}{16} { \times }^{3} . \frac{1}{ {y}^{2} } \\ = \frac{ { \times }^{3} }{16 {y}^{2} } \\ \\ \\ b. {2}^{5} a { - }^{3} b {}^{5}c { - }^{2} \\ = {2}^{5} a { - }^{3} {b}^{5} c { - }^{2} \\ = 32a { - }^{3} {b}^{5} c { - }^{2} \\ = 32 \times \frac{1}{ {a}^{3} } \times {b}^{5} . \frac{1}{ {c}^{2} } \\ = \frac{32 {b}^{5} }{a {}^{3} {c}^{2} } \\ \\ \\ {semoga \: membantu}[/tex]
a ). (-4)^-2 x^3 y^-2= (-4)^-2 x^3 y^-2
= 4^-2 x^3 y^-2
= 1/4^2 . x^3 . 1/y^2
= 1/16 . x^3 . 1/y^2
= 1/16x^3 . 1/y^2
= x^3 / 16y^2
kalau kurang jelas bilang ya [answer.2.content]
